Can I still rely on the order of the output elements when using par_unseq?

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After reading the documentation I'm still confused about the usage of par_unseq. I know I can't tell anything about the order of execution because of threading and vectorization but can I still rely on the order of the outputs?

transform([x0, x1, x2], f) == [f(x0), f(x1), f(x2)]] 

In order words, is this test ever going to fail?

std::vector<int> xs = {1, 2, 3, 4}; std::vector<int> ys(xs.size());  std::transform(     std::execution::par_unseq,     cbegin(xs), cend(xs),     begin(ys),     [](int x) { return x*x; });  std::vector<int> expected = {1, 4, 9, 16}; ASSERT_EQ(expected , ys); 

 


The Standard, [alg.transform], reads:

Effects: Assigns through every iterator i in the range [result,result + (last1 - first1)) a new corresponding value equal to op(*(first1 + (i - result)) or binary_op(*(first1 + (i - result)), *(first2 + (i - result))).

and (thanks, @Caleth), [algorithms.parallel.overloads]:

Unless otherwise specified, the semantics of ExecutionPolicy algorithm overloads are identical to their overloads without.

So, yes, you can rely on the order in the output.

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