- A+

I wanted to see what the smallest number divisible by all one digit numbers was and instead of looking it up I created this.

`public static void main(String[] args) { for (int i = 100; i < 10000; i++) { if (i % 2 ==0) { if (i % 3 ==0) { if (i % 4 ==0) { if (i % 5 ==0) { if (i % 6 ==0) { if (i % 7 ==0) { if (i % 8 ==0) { if (i % 9 ==0) { System.out.println(i); break; } } } } } } } } } } `

As you can see, I have an if statement in an if statement x9. The code worked but I wanted to condense my if statements using an array to make my if statement like this but it didn't work.

` if (i % x[1, 2, 3, 4, 5, 6, 7, 8]) { System.out.println(i); break; } `

Any suggestions?

At first you would think you can test all of them at once by placing the product of 2 through 9 on the right side of the `%`

operator.

`if (i % (2 * 3 * 4 * 5 * 6 * 7 * 8 * 9) == 0) `

But because certain numbers include previous numbers in their factorization, you should use a lower number, specifically, the least common multiple. 8 is a multiple of 2 and 4, 9 is a multiple of 3, and if 8 and 9 are in the product, then 6 (2 * 3) is covered too.

`if (i % (5 * 7 * 8 * 9) == 0) `