# Is integer division always equal to the floor of regular division?

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For large quotients, integer division (`//`) doesn't seem to be necessarily equal to the floor of regular division (`math.floor(a/b)`).

According to Python docs (https://docs.python.org/3/reference/expressions.html - 6.7),

floor division of integers results in an integer; the result is that of mathematical division with the ‘floor’ function applied to the result.

However,

``math.floor(648705536316023400 / 7) = 92672219473717632  648705536316023400 // 7 = 92672219473717628 ``

`'{0:.10f}'.format(648705536316023400 / 7)` yields '92672219473717632.0000000000', but the last two digits of the decimal part should be 28 and not 32.

The reason the quotients in your test case are not equal is that in the `math.floor(a/b)` case, the result is calculated with floating point arithmetic (IEEE-754 64-bit), which means there is a maximum precision. The quotient you have there is larger than the 253 limit above which floating point is no longer accurate up to the unit.

With the integer division however, Python uses its unlimited integer range, and so that result is correct.