# Average of even numbers gives back wrong value

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Category：Languages

I am trying to get closer to understanding streams thus I'm doing some basic exercises. In this one, I'd like to calculate the average of the odd numbers. I wrote this algorithm to do so, but it gives back an incorrect result (8.0). I've tried to debug it but I couldn't find what it does actually.

``List<Integer> numbers = Arrays.asList(1, 3, -2, -4, -7, -3, -8, 12, 19, 6, 9, 10, 14);  OptionalDouble result = numbers.stream()                                .filter(i -> i % 2 == 1)                                .mapToDouble(i -> i).average(); if (result.isPresent()) {    System.out.println(result); } else {    System.out.println("Error"); } ``

What is my code doing now? How should I fix it to do what it's supposed to do?

``(i -> i % 2 == 1) ``

This is only true for positive odd numbers, because in Java the `%` operator returns a negative number (or zero) if its first operand is negative.

If you want to retain only even numbers, it should be:

``(i -> i % 2 == 0) ``

If you want to retain all odd numbers (positive and negative), you can use:

``(i -> i % 2 != 0) ``