- A+

Create a function called mulitples0f It will accept two arguments, the first will be an array of numbers, the second will be a number. The function should return a new array that is made up of every number from the argument array that is a multiple of the argument number. So multiplesOf([5,6,7,8,9,10],3) will return [6,9]

`function multiplesOf(numbers) { var multiples = numbers[0]; for (var i = 0; i < numbers.length; i++) { if (numbers[i] % multiples === 0) { multiples = numbers[i]; } } return multiples; } console.log(multiplesOf([4, 5, 6, 7, 8], 2));`

says function is defined in jsbin help please

You have a few issues with your code. At the moment `multiplesOf`

only accepts 1 argument when it should be two, ie, the `numbers`

array and a single `number`

Your other issue is that you are not keeping an array of the multiples found, instead, you are setting a variable to the multiples found and is getting overwritten when a new multiple if found (thus leaving you with the very last multiple found in the array). Instead, you want to change your `multiples`

variable to an array. This way you can `push`

every multiple found into this array.

See working example below (read code comments for changes):

`function multiplesOf(numbers, number) { // add second argument var multiples = []; // change to array (so that we can store multiple numbers - not just one multiple) for (var i = 0; i < numbers.length; i++) { if (numbers[i] % number === 0) { // divide by the number multiples.push(numbers[i]); // add the current multiple found to the multiples array } } return multiples; } console.log(multiplesOf([4, 5, 6, 7, 8], 2)); // Output: [4, 6, 8]`