What is the purpose of marking the set function (setter) as constexpr? [duplicate]

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I cannot understand the purpose of marking the setter function as constexpr, that is allowed since C++14. My misunderstanding comes from the next situation: I declare a class with a constexpr c-tor, and I am about to use it in a constexpr context, by creating a constexpr instance of that class constexpr Point p1. An object p1 now is constant and its value could not be changed, so the constexpr setter could not be called. On the other hand, when I create an instance of my class Point in a non-constexpr context Point p, I can call the setter for that object, but now setter will not execute at compile-time, because the object is not constexpr!

As a result, I do not understand how can I enhance the performance of my code using constexpr for setters.

This is the code that demonstrates calling a constexpr setter on an non-constexpr object, that means run-time computation, instead of the compile-time:

class Point { public:     constexpr Point(int a, int b)     : x(a), y(b) {}      constexpr int getX() const noexcept { return x; }     constexpr int getY() const noexcept { return y; }      constexpr void setX(int newX) noexcept { x = newX; }     constexpr void setY(int newY) noexcept { y = newY; } private:     int x;     int y; };   int main() {     Point p{4, 2};     constexpr Point p1{4, 2};      p.setX(2); } 

Could anyone help me to understand what is the purpose of marking the setter function as constexpr?


Basically it is nice when you have to deal with constexpr function.

struct Object {   constexpr void set(int n);   int m_n = 0; };  constexpr Object function() {    Object a;    a.set(5);    return a; }  constexpr Object a = function();  

The idea is to be able to perform compile time initialization within another functions that will be executed at the compile time. It is not done to be applied on constexpr object.

Another things to know is that constexpr member functions are not const member functions since C++14 :).


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