Say I have a classWith ambiguous types enabled, I could specify each of them in an instance:If I want to make tag2 append something to tag1, I can define
I am currently reading Learn You a Haskell for Great Good! and am stumbling on the explanation for the evaluation of a certain code block. I've read the explanations several times and am starting to doubt if even the author understands what this piece of code is doing.
The benefit of this could be to store certain metadata about the type in a canonical location. Sometimes, it isn't convenient to have a value of the type before using some instance methods on it; For instance if I have:
I encountered this example while reading Learn You a Haskell for Great Good.I don't quite see how to treat $ as function application. Does that mean $ is an operator? But if so, how it will be nested with + or * in the example? I tried $ 3 4+,...
The function type would be Tree a -> Tree (a, Int). I want to carry the count through out the tree and number each occurring leaf accordingly.
I'm trying to learn haskell after years of OOP. I'm reading Happy Haskell. It provides this code:I understand how plus and plus' work (they're the same, different syntax). But increment, I don't get.
The example is taken from a "Haskell programming from first principles" The goal of filter function is get rid of all the objects except those of 'DbDate' type.
I am currently learning me a Haskell, so for so good.I am pretty fluent when it comes to F# and I want to try my hand at pure functional programming.
Scratching at the surface of Haskell's type system, ran this:Somehow, despite en and ec have different types, they both test True on == e. I say "somehow" not because I am surprised (I am not), but because I don't know what is the name of rule/mechanism that allows this. It...
I'm Trying to figure out how I can Sum up the Arguments of a Function which has a given signature sum :: Int -> ... -> Int with 1024 Int arguments...