I've written the following (trivial) function:I'd've expected this to be desugared as:In turn, desugared (ignoring the fail stuff) as:
Is there a way to write do notation for a monad in a function which the return type isn't of said monad?
Type signature of Haskell's bind operator (>>=):Type signature of F#'s forward pipe operator (|>):They look similar. And considering the impure nature of F#, the equivalent operator of |> in Haskell is >>=?
Obviously, if a data structure is a monoid, it's foldable, but is it safe to say if a data structure is foldable, it's a monoid?
For instance, suppose I want to read a line and also ring a bell:The idea seems to have much in common with const, the only difference being that the values given are effectful, and are both executed, even though only the value of the first action is retained. (Unlike with...
In the following code snippet I initially believed to have a restricted monad error (I forgot to add the Monad m => in the instance Monad (Transform m a) definition). Having read quite a bit about restricted monads I wonder why this here happens to be ok:
From my readings I understand that Monads are mainly used for:-Function Composition by matching one Functions Output Type to another Functions Input Type.
In order to refresh my 20 year old experience with Haskell I am walking through https://en.wikibooks.org/wiki/Write_Yourself_a_Scheme_in_48_Hours/Adding_Variables_and_Assignment and at one point the following line is introduced to apply op to all the params. This is to implement e.g. (+ 1 2 3 4)
Since I'm fairly new to Rust, I need guidance on how error handling is done idiomatically. I find the error-handling boilerplate really annoying.
I have the following code which grabs two pages of data from a paginated API endpoint. I'd like to modify query function to keep getting pages until it finds no more data (so replace take 2 in the code below with something which looks at the API response).