A super simple question:Here's my plain Java code using traditional ternary operator ?My best bet is following:
I run SonarQube to check my code and I found a case which I don't understand the reported error.My code is:
I'm trying to do this:Really, what I want is to return an Optional.of(foundVal) if found, otherwise Optional.empty(). I don't believe Optional.of(null) equates to that. What syntax does what I want to do?
For optional's template<class U = T> optional<T>& operator=(U&& v); the standard demands that (see [optional.assign]/3.16):
I just wanted to return a boolean from an Optional object by doing a check on the getProductType() on the ProductDetails object as shown below:
I have this code below. The findfirst call is thwowing NullPointerException even though I have an orElseGet call chained
The following code compiles without warning:Makes sense... Any is any type, value type or reference type.
I have the classic "Elvis operator" case, where I'm calling methods that each may return null and chaining them together:
I'm trying to write syntactic sugar, in a monad-style, over std::optional. Please consider:As is, this function cannot be called with a non-optional T1 (e.g. an int), even though there exists a conversion from T to std::optional<T>2.
I have an instance of OptionalLong. But one of my libraries requires an Optional<Long> as parameter. How can I transform it?