So, I wrote something like thisAnd it printedI'm a bit confused:Is this well-defined behaviour, or is it implementation specific?
Try out this following code:You'll see a compile error:Is there any way to workaround this ambiguity? Perhaps with SFINAE?
I was trying to create two classes, the first with a non-const implementation of the functions, the second with a const implementation. Here is a small example:
Doing an experiment of translating .NET IL to C++ in a human readable fashion.Here is the issue: C# allows you to resolve multiple interfaces with the same method name that only differ in return type. C++ doesn't seem to support this however making resolving two interfaces impossible using the vTable...
Coding stuff after taking the hint from my previous question's answer, I ran into an issue with overloading Scene::addObject.
I want to have a struct that takes an arbitrary number of lambdas and serve as a central calling point for all their call operators.
This question already has an answer here:I have this example C# code:Calling Main() ends up printing:
I'm trying to write a class that takes two templated types. This class inherits from an interface. See the below code.
I have a third-party assembly that has a huge struct with lots of members of different types in it. I need to take some of the values from that struct and process them. So I write overloads for different types. I know what I need to do with ints, with...
In C++, for the operator greater than or equal to (">="), is it enough to have the operators equal ("=") and greater (">") overloaded to have functionality for the greater than or equal to (">=")? Or do I need to overload the operator (">=") to have functionality for it?