I'm aware of how to get the last argument passed to a function but I'm wondering how to get all the arguments of a function after the first two:
I have file with content:file.txt:In this file between every First launch, content can be different, it is not fixed ( for example: First launch 3 contain three elements while First launch 2 contents only 2 elements), so any number of content can be between the First launch pattern which is...
I have searched for a similar question here, but surprisingly could not find any.In GNU bash, there is (a construct? a structure? a data type?) called "arrays". Arrays are well documented in the bash documentation, so I think that I understand the basics.
In a folder, I would like to print the name of every .txt files that contain n=27 lines or fewer lines. I could do
Usually, we run commands on terminal/tty/command window in the linux system. If we run ls -l ,we know that, we actually start execute a file named ls located /bin, which full path is /bin/ls.
Cannot seem to find an answer to this one online...I have a string variable (externally sourced) with new lines "/n" encoded as strings.
I have a .pl file that consists of an unstructured header and some specific X Y Z structure. The header has no "." in there. Below you can find a snippet of this file:
I have a variable VarExp with following 2 valuesI have another variable VarCurr with following 1 value
I have two scripts, namely shell_script.sh and perl_script.pl. shell_script.sh : It has function definitions which, when invoked from Perl script, will execute certain commands on Linux in batch mode.
I have this data:And this command:I get the following output:How can I change this sed expression to not match the final line of the output? So the ideal output should be: