I was reading about strict aliasing, but its still kinda foggy and I am never sure where is the line of defined / undefined behaviour. The most detailed post i found concentrates on C. So it would be nice if you could tell me if this is allowed and what...
According to the standard, it is always undefined behavior in C++ to make, for example, a float* point to the same memory location as a int*, and then read/write from them.
This is a follow up to this other question about memory re-use. As the original question was about a specific implementation, the answer was related to that specific implementation.
I've been using std::memcpy to circumvent strict aliasing for a long time.For example, inspecting a float, like this:
In one particular C++ function, I happen to have a pointer to a big buffer of floats that I want to temporarily use to store half the number of doubles. Is there a method to use this buffer as scratch space for storing the doubles, which is also allowed (i.e.,...
Suppose I have a chunk of dynamically allocated data:I wish to use the data pointed at by foo as a special type, type_t. But I want to do this later, and not during allocation. In order to give the allocated data an effective type, I can therefore do something like:
ISO C requires that hosted implementations call a function named main. If the program receives arguments, they are received as an array of char* pointers, the second argument in main's definition int main(int argc, char* argv).
Sample code:I believe this is common and considered acceptable. The standard does guarantee that there is no initial padding in the struct. However this case is not listed in the strict aliasing rule (C++17 [basic.lval]/11):