I have a table with a string column formatted like thisAnd I would like to extract the last word in that filename. So I think the beginning pattern would be the word "Work" and ending pattern would be ".csv". I wrote something using grepl but not working.
Suppose I have a data frame like this with a string vector, var2What is the most efficient way to split var2 every n characters into new columns until the end of each string,
Rosettacode.org has this excellent one-line FizzBuzz solution in Ruby.The trouble is, I don’t understand it. The part that puzzles me is the ”n to the power of 4 modulo -15”. Does anyone have an explanation or a reference to an explanation? I want to use this way of selecting substrings...
I want to delete everything in this column 3 characters after '18'I want my output to look likeI have tried the following code.
I'm working on a Speech Recogniser module in my app. Speech recogniser return a string (may be some time with garbage string information, closely matching with user's speech) and I have to evaluate specific command from a string.