I need to sort an array of elements based on their frequency, for example:I tried with the code below:
I wrote a java routine to compare 2 binary trees. I am looking for better algorithms that run in less time.
This is a question that I was asked in an interview: Implement a function that gets an integer n and does the following: 1. if n is 3 -> return 7. 2. else if n is 7 -> return 3. 3. otherwise return any number you like (undefined behavior).
This question already has an answer here:I have written code for two approaches to find out the first unique character in a string on LeetCode.
I have written code for 2 approaches to find out the first unique character in a string on LeetCode.Problem Statement: Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.
is there a data structure in c++ that has a search time complexity of O(1)? As in to check if an element is present in it or not, and if present, what its position or associated index/ key/value is
I am a bit confused, to be honest. I was working out the one of the classical algorithm problems. Given a collection of integers, find if are there 2 elements summing to a given number.
I'm doing some regex problems from a textbook and of them reads the following:"[Match] all strings that start at the beginning of the line with an integer and that end at the end of the line with a word."
Please take a look at the std::advance function. According to cppreference the complexity is:Linear. However, if InputIt additionally meets the requirements of RandomAccessIterator, complexity is constant.
The .split_off method on std::collections::LinkedList is described as having a O(n) time complexity. From the (docs):